argh mixing, of course!
Ln(I) = Ln(D) + Ln(V) - V/B
Ln(I) - Ln(V) = Ln(D) - V/B
Ln(I/V) = Ln(D) - V/B
Ln(I/V) vs V
Ln(D) is the y-intercept.
-1/B is the gradient.
I think that's it.
Thanks tiny-tim! much appreciated.
Homework Statement
Hi, I need to produce a linearized equation of the following,
I = D. V. exp(-V/B) eq(1)
I is the current
V is the voltage
D is a constant
B is a constant
Data was collected in an experiment designed to investigate the characteristics of a...