Recent content by rkiecaboose

So...can someone tell me if this is correct? Since I know the gravitational potential energy (U) is mgh on earth. It gives me 490J assuming a mass of 50kg. I used the same equation U=mgh, solving for h gives: U/mg=h. Since the gravitational acceleration is GM/R2 the acceleration on the new...

Well if we're considering the initial point to be grounded wouldn't the initial just be 0 on both planets? I'm lost as to how to relate Earth to the unknown

Sorry I posted the question initially while I went and grabbed my work. Newtons universal law of gravitation... F=GM1M2/R2 Though I don't know where I would use it. Am I on the right track using conservation of energy but instead of using mgh use -GM/r ?

Homework Statement Knowing you can jump about 1m high on Earth's surface, how high can you jump on the unknown planet. Munknown= 4.19*10^21kg Radius Unknown= 1*10^6m Homework Equations Not sure if can be used in this question K1+U1 = K2 + U2 1/2MV2 + mgh = 1/2MV2 + mgh U=-GM/r and U = mgh...