Recent content by rlc

(105.95*answerA with units"c")/squareroot[1-(answerA with units "c")^2]

SQRT(1-(To/T)^2) Sorry, I kept forgetting the squared and I put them out of order. This worked for part a, but would this be 1/sqrt or just the sqrt?

Would that be: 1/SQRT(1-(T/T0)) ?

Would T and T0 have the same values in the calculation for momentum as they did in the calculation for speed? p=(m)(v) / SQRT(1-(T/T0)) ?

I'm sorry, I just really don't understand.

p=[1/SQRT(1-(2.2/14.718)^2]*(mass)(velocity) where mass=207*9E-31=12439 velocity is what I solved for in part a: 2.966E8 Did I miss something?

Oh, so would I use the average lifetime at rest value and the average accelerated lifetime value in this equation as well?

So would this equation end up working? p=(m)(v) / SQRT(1-(v^2)/(c^2))

Is this for calculating KE or momentum?

p=(m)(v) / SQRT(1-(v^2)/(c^2)) Where would the kinetic energy be in the equation?

Homework Statement The average lifetime of muons at rest is 2.20 μs. A laboratory measurement on muons traveling in a beam emerging from a particle accelerator yields an average muon lifetime of 14.718 μs. a) What is the speed of the muons in the laboratory? b) What is their kinetic energy...

Thank you! The answer ended up being 1.00 It's pretty clear I haven't taken a math class in a while... :)

Homework Statement Find the speed parameter β and Lorentz factor γ for an electron that has a kinetic energy of: a) 6.00 keV b) 2.00 MeV c) 4.00 GeV Homework Equations KE=(γ-1)*511 KeV SQRT(1/(1-β^2))=γ The Attempt at a Solution a) 6 KeV=(y-1)*511 y=1.0117 1.0117=SQRT(1/(1-β^2)) β=0.152 b)...

(n3)sin(beta)=(n4)sin(90) (1.20)sin(beta)=(1.00)sin90 beta=56.44 (n2)sin(alpha)=(n3)sin(beta) (1.42)sin(alpha)=(1.20)sin(56.44) alpha=44.7669 (n1)sin(theta1)=(n2)sin(alpha) (1.58)sin(theta1)=(1.42)sin(44.7669) theta1=39.26 deg