Recent content by RMalt

Attached are my diagram drawings. DO you agree? What improvements can be made?

Hi again, I am starting to think that my diagram i drew is correct. That is because the isobaric process starts at point 1 however as this process is ongoing, the volume is decreasing. So the isochoric process starts at a lesser volume than the initial. If it was drawn the other way it would...

Thanks for your time on this matter. I will see what I can manage.

I know that general gas law can be applied in this case, and also: Boyle's Law: PV = k Gay-Lussac's Law: P/T =k Charles Law: V/T =k However for the T-V diagram of an isochoric process this cannot be done by applying the above laws, or can it ? Since temperature may vary while volume remains...

Homework Statement [/B] This is a very basic question. I have a cylinder filled with air having stops at a particular height . First part of the process is isobaric as piston is free to move and P is constant. When piston reaches stops this becomes isochoric process as volume is constant. So...

I think i found a mistake in your calculation: Shouldnt you also be dividing by gravity ?? 1 − 2 = (2 −1)ℎ

Edit: Was v1 calculated or was it given?Calculated

Hi, thanks for your time and insight on this matter. However, unfortunately this is not one of my strong subjects. I re-worked some calculations and got P1 = 60.3kPa as is yours. Can I use the formula ρ*Hg*h = p1 ? I found this other formula not taking into consideration the density of water...

Homework Statement so I have been working on this problem : Diameter1 at wide end: 8cm || V1 = 1.56m/s Diameter2 at narrow end: 3cm || V2 = 11.094m/s Force exerted on plate = 87N Find the manometer reading Picture below: Homework Equations P1+(1/2 ρv1^2)=P2+(1/2 ρv2^2) 1 − 2 = (2 −1)ℎThe...

Thanks all for your help ! Now, on to the next questions ! :wink::nb)

v^2 = F/(density x A) v^2 = 87/(1000 x 7.01 x10-4 ) v = 11.1 m/sMy area is in m sqaured

Using this equation the velocity will be really small ! F=ρv2A 87 = 1000 * v2 *7.0685 V2 = 0.111 cm/s . Does a value of this magnetude make sense ?

Thanks for your insight on this matter. This means that ,F/A2=p2+density/2(v2^2) (given earlier) is incorrect ? Or am I still missing something here?

I came across this video while doing research however it does not match with the formula I was given earlier on. Can anyone confirm if this video is correct ?

So I end up with : 12.3 = p2 + 1000/2(V2^2) . Should P2 be taken as 0 in this case since it is at atmospheric pressure ?