Roberto Pavani's latest activity

Exagonal (L=R) area minus half circle (R=R) area? Exagon vertex are 3 circle centers plus 3 figure vertex

I've found this article that seems related: https://arxiv.org/html/2607.03415v2. However it seems to me that some kind of "extra time"...

You are right. I'm using the OP's own wording. I was asking for clarification of QuarkMeson's answer to the OP, which wasn't clear to me.

Probably my question was malformed. I was asking clarification about your statement: I think this could mean two different things: 1)...

There are maybe a dozen or two preprints filed in the General Relativity and Cosmology category of arXiv on this subject every year (I...

Do you mean that those extra dimensions do not interact, or that the interaction is infinitesimal? Both assertions are ok, but the first...

Get an IDE (e.g Eclipse or VisualStudio or... plenty of...) If you want to do Android programs, AndroidStudio. Get the AI assistant...

Are you talking to me? Note this sentence in my post #25: Try your integral but this time use an actual cosmological constant. What...

My fault. I didn't realize you meant a constant "cosmological constant".

Doesn't this requires that ## \int_{t_0}^{\infty}\frac{dt}{a(t)} ## to be finite ? Acceleration itself doesn't allow this. As an...

For the sake of clarity regarding terms: The particle horizon is the current distance to the farthest comoving object from which, in...

Proper time can't be a coordinate, because different observers that follow different worldlines between the same two events can have...

Strongly agree

Yes, we can Note: acceleration is ## \approx 9.81 \frac m { s^2 } ## because ## g \propto \frac 1 { R^2 } ##

V = 0 doesn't matter. Throw C upward: at the top ## v=0 ## for an instant, but C ir's still free-falling all the time (accelerometer =...