Roberto Pavani's latest activity

Fair point, let me sharpen the example. Replace the two coins with two entangled qubits (singlet state). Now the combinatorially...

Thank you for the clarification on terminology, I agree that "decoherence has occurred" is more precise than "not in superposition."...

Fair enough, whether it's a strict continuum or a countable infinity is probably not essential to the point, and that's just for a...

Thank you for confirming the recoil decoherence. But then, since the recoil can occur in any direction on the sphere, doesn't that imply...

But the particle doesn't need a local detector, sooner or later it will interact with something, even if it takes eons. The direction of...

Let me simplify with an even cleaner example: alpha decay. ²³⁸U → ²³⁴Th + α One nucleus. One alpha particle flies off. In which...

Following #48: so the number of branches can be a continuous infinity. My estimate of 2^(10²⁴⁵) in #29 was potentially wrong, but still...

My estimate in #29 uses the same logic as the standard vacuum energy calculation that gives the 10¹²⁰ cosmological constant problem...

Expanding on this point (if I understand MWI): if we associate even a single binary degree of freedom to each spacetime "slot" at the...

Which is irrelevant to the MWI, because the MWI says that it only takes one run of the 1000 coin tosses experiment to get the 1000 heads...

No, you're seeing an objection that many others (myself included) also see to the MWI.

PS it's also not clear how our conscious experience arises from MWI. In a collapse interpretation, QM is a model for a single universe...

Yes, in MWI there are possibly branches where people are throwing away their physics books. However: there is no way to distinguish...

In a single universe, yes, once every ~2^1000 repetitions. But in MWI, that branch exists right now, at every branching. You don't need...

In classical coin tossing, only one sequence is realized. In MWI, all sequences are realized. The question isn't 'why is 1000 heads...