Hi,
Say I have this pde:
u_t=\alpha u_{xx}
u(0,t)=\sin{x}+\sin{2x}
u(L,t)=0
I know the solution for the pde below is v(x,t):
v_t=\alpha v_{xx}
v(0,t)=\sin{x}
v(L,t)=0
And I know the solution for the pde below is w(x,t)
w_t=\alpha w_{xx}
w(0,t)=\sin{2x}
w(L,t)=0
Would...