- #1
robl123
- 2
- 0
Hi,
Say I have this pde:
[itex]u_t=\alpha u_{xx}[/itex]
[itex]u(0,t)=\sin{x}+\sin{2x}[/itex]
[itex]u(L,t)=0[/itex]
I know the solution for the pde below is v(x,t):
[itex]v_t=\alpha v_{xx}[/itex]
[itex]v(0,t)=\sin{x}[/itex]
[itex]v(L,t)=0[/itex]
And I know the solution for the pde below is w(x,t)
[itex]w_t=\alpha w_{xx}[/itex]
[itex]w(0,t)=\sin{2x}[/itex]
[itex]w(L,t)=0[/itex]
Would the complete solution be u(x,t)=v(x,t)+w(x,t)?
Say I have this pde:
[itex]u_t=\alpha u_{xx}[/itex]
[itex]u(0,t)=\sin{x}+\sin{2x}[/itex]
[itex]u(L,t)=0[/itex]
I know the solution for the pde below is v(x,t):
[itex]v_t=\alpha v_{xx}[/itex]
[itex]v(0,t)=\sin{x}[/itex]
[itex]v(L,t)=0[/itex]
And I know the solution for the pde below is w(x,t)
[itex]w_t=\alpha w_{xx}[/itex]
[itex]w(0,t)=\sin{2x}[/itex]
[itex]w(L,t)=0[/itex]
Would the complete solution be u(x,t)=v(x,t)+w(x,t)?