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Here is my work: 2SO2(g) + O2(g) ↔ 2 SO3(g) 2n 0 ↔ 2n -2n@ -n@ ↔ +2n@ 2n-2n@ -n@ ↔ 2n +2n@ Where Nt= 2n-2n@-n@+2n+2n@ 2n(1-@) -n@ ↔ 2n(1+@) Nt=4n-n@ Nt= n(4-@) 2n(1-@)/n(4-@) -n@/(n4-@) ↔ 2n(1+@)/ (n (4-@))...

Chemical equilibrium help! For a reaction 2SO2(g) + O2(g) ↔ 2 SO3(g), 0.1mol of each SO2 and SO3 are mixed in a 2.0L flask at 27 degrees Celsius. After Equilibrium total pressure is 2.78atm. Calculate a) The mole fraction of O2 at equilibrium b) The value of Kp I don't know how to find out...