Recent content by rockerdoctor

Im a senior in high school. i have about a B average. i got a 26 on the act. i have taken 4 years of math including pre-calc and trig, along with chemistry, physics and IB physics (basically ap physics), chemistry, AP biology. I am really interested in going to graduate school and getting an...

I am going to major in physics with either a minor or double major in astronomy and was wondering if anyone could tell me if DePauw has a relativly good physics program. If not, any other suggestions for schools. thanks!

That looks right to me. The only thing wrong is your wording. It is centripetal acceleration not centrifugal.

that is what i got too.

it would be positive because the compression in the same direction as the velocity you use.

yes the velocity will be 0 at the point of maximum compression. but that's not what you want to use. you want to find the kinetic energy before it compresses the spring. so use the .5mv^2 before it gets to the spring and set things equal. sorry for the last post, i didnt see you had the...

the equations you will want to use are Ek= (1/2)(m)(v^2 - u^2) where u is the initial velocity Eel= (1/2)(constant)(Δx^2) where Δx is how far the spring is compressed. see if you can figure out where to go from there.

guitar 3 years, violin 9 years and piano off and on for about 6 years but not very good, bass guitar about 6 months.

Im not really sure what the question is... but just based on the i would start by finding the kinetic energy of the block, since we know the surface is frictionless, think about where all that energy has to go when it hits the spring.

not all the equations to find work requires distance. do you know what the formula for kinetic energy is?

First off, draw a picture. Once you have that think of what work and power really are. how do you find work? how do you find power? what equations do you use? i also think it may be better to figure out number 2 before number one. but that my be just me.

"negative because you are decelerating in the negative x direction." sorry, that is worded poorly. it should say, because you are decelerating in the positive x direction, meaning you are accelerating in the negative direction.

i tried it a slightly different way and got the same answer, only negative. i did 2aΔx=v²-u² where u=inital velocity, v=final velocity,a=acceleration and x being displacement. so using that i got a= (v²-u²)/2Δx Fnet=ma Fnet= m ((v²-u²)/2Δx) plug all the numbers in and you get...

You have to have either the time or the acceleration to find the force. Absent of acceleration the way to find force would be to use the momentum equations. p=mv p=(Fnet)*(Δt) therefore... (Fnet)*(Δt)=mv Fnet=(mv)/(Δt)

if an object is moving at a constant velocity it doesn't have a force in that direction. Fnet=ma. Force=mass*acceleration, not velocity. that's momentum. a net force of 0 just means there is no acceleration. a net force shows an objects acceleration. i would say the easiest way to look at this...