Recent content by RockPaper

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    Solve L'Hospital's Rule: sin(e^(x^2)-1)/e^(cosx)-e

    Great! Thank you for the help... I actually added the parenthesis on my paper but somehow didn't do that when I wrote it on the computer. :| It took me a whole bunch of tries to get this right (even when I had an idea on what to do), I need to work on my math skills which I'm hoping to get...
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    Solve L'Hospital's Rule: sin(e^(x^2)-1)/e^(cosx)-e

    I'm glad I finally got it because it took me a few tries to get it :/ which is typical. I don't understand how it's 4x3. And thank you for telling me that it's 4x^2e^(2x^2) because I didn't know how to simplify it :shy:
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    Solve L'Hospital's Rule: sin(e^(x^2)-1)/e^(cosx)-e

    Thank you for clearing that up, so the limit as x->0 is 0 I get: 2ex2+4x2ex2cos(ex2-1)-sin(ex2-1)*2xex2*2xex2
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    Solve L'Hospital's Rule: sin(e^(x^2)-1)/e^(cosx)-e

    I think you're right Bohrok (because I have a tendency of messing up). @Bohrok: Do you mean the second differentiation should be -sin(ex2-1)2xex2+(2ex2+4x2ex2)cos(ex2-1)/-cos(x)ecosxsin2x*ecosx also, would the negative signs go away since we have both in the numerator and denominator? could...
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    Solve L'Hospital's Rule: sin(e^(x^2)-1)/e^(cosx)-e

    Homework Statement lim as x -> 0 sin(e^(x^2)-1)/e^(cosx)-e See Link Below. I saw this on the net and tried to solve it. I'm wondering if I'm correct by any means or did I mess up somewhere along the line. Homework EquationsThe Attempt at a Solution...