Recent content by rodolfomz

thats what I have ## ∫\frac {dy}{y*ln(y+1)}=∫dx ## changing variables ## u=ln(y+1) ; du=\frac{dy}{y+1} ## ##\int \frac{e^u*du}{(u)*(e^u -1)} = x ## which is the same as ##\int \frac{du}{u}*\frac{e^u}{e^u-1} = x## and then resolving by parts dv= du/u and u=e^u/e^u-1...

Homework Statement Find the solution to ## \frac{dy}{dx} = yLn(y + 1) ## Homework Equations ## \frac{dy}{dx} = yLn(y + 1) ## The Attempt at a Solution ## \frac{dy}{dx} = yLn(y + 1)## ## \frac{dy}{yLn(y + 1)} = dx ## but then i can't integrate, any help?