Recent content by rogerthat4

Or should it be this, = DQ = DT/ (L1/k1A + L2/k2A) where L = length of the rod. A = cross sectional area of rod. i had, DQ = DT / (1/k1A + 1/k2A) Is it dependent on the length?

Thanks for your help!

I just need the equation, i am not going to derive everything from first principles, you can see what i have done, Dt / sum of R where, R is as stated. I am not William Thomson attempting to experimentally derive with this conclusion, i just have asked for a verification of the above...

I think this is the answer, not 100%, delta Q = delta T / SUM ( R ) => DQ = DT / R1+R2...+...R0 R1 = 1 / k1A , R2 = 1 / k2A ,..., R0 = 1 / k0A

Homework Statement Hello, first question here, A copper rod and an aluminium rod are in thermal equilibrium with each other. Copper rod = 50cm long and the aluminium rod is 20cm. Radius of pair is 8cm. Copper end is heated (and maintained) at 80C , other end of pairing is 20C. k of...