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Yes, you are right! Thank you a lot! Is this solution a correct? By Gauss' law: ##\frac{q}{\varepsilon_0} = ES_{full}## ##\frac{q}{\varepsilon_0} = 2ES## ##E = \frac{q}{2\varepsilon_0S}## ##E = \frac{\sigma}{2\varepsilon_0}## ##E_{ind} = E_{ind+} + E_{ind-}## ##E_{ind} =...

No, it doesn't fix it: ##E_{in} = \frac{\varepsilon_0E_{out}}{\varepsilon}## ##E_{ind} = E_{out} - E_{in}## ##E_{ind} = E_{out} - \frac{\varepsilon_0E_{out}}{\varepsilon}## ##\sigma = \left( E_{out} - \frac{\varepsilon_0E_{out}}{\varepsilon} \right)\varepsilon_0\varepsilon## ##\sigma =...

The correct answer to this problem is: ##\sigma = \varepsilon_0E\frac{\varepsilon-1}{\varepsilon}## Here is my attempt to solve it, please tell me what is my mistake? ##E_{in} = E_{out} - E_{ind}## ##E_{ind} = E_{out} - E_{in}## ##E_{in} = \frac{E_{out}}{\varepsilon}## ##E_{ind} = E_{out} -...

Hello everyone! I recently started studying physics on my own.