Recent content by Rookie
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Rocket Thrust, Acceleration, Velocity and Altitude
Sorry here is the link: http://www.calculatorsoup.com/calculators/physics/displacement_v_a_t.php- Rookie
- Post #17
- Forum: Introductory Physics Homework Help
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Rocket Thrust, Acceleration, Velocity and Altitude
Oh it came from https://www.google.com.au/webhp?sourceid=chrome-instant&ion=1&espv=2&es_th=1&ie=UTF-8#q=distance%20calculator%20physics&safe=off except I tried to put gravity on the end of it. The course unit is Physics of Games (seconds year uni subject), there were no prerequisites for...- Rookie
- Post #15
- Forum: Introductory Physics Homework Help
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What is the Separation of Two Apertures in a Light Diffraction Grating?
Ahh second order, I had m = 0 which is zeroth order. So m should equal 2?- Rookie
- Post #3
- Forum: Introductory Physics Homework Help
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What is the Separation of Two Apertures in a Light Diffraction Grating?
Homework Statement A source of light shines through two apertures resulting in an intensity distribution pattern on a viewing screen. The central bright fringe is called the m=0 or zeroth order maximum. In the schematic diagram 1, the light source is to the left of the page and the point...- Rookie
- Thread
- Diffraction Light
- Replies: 2
- Forum: Introductory Physics Homework Help
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Rocket Thrust, Acceleration, Velocity and Altitude
v = v0 + u * ln(M0 / Mt) - gt I put the subscript on the first M, 0 for the original mass, then the subscript t on the second for mass at the given time; M1 = 3625 (d) Calculate the altitude reached after 1 second. x = v0t + 0.5 * at2 - gt a = 150,000 / 3625 - 10 = 31.38 x = 0 + 0.5 *...- Rookie
- Post #13
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
Sure thing. Thank you.- Rookie
- Post #37
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
THANK YOU SUCH MUCH GUYS! Really thank you. I can now sleep in ease. I will remember to properly solve the equation step by step on my exam!- Rookie
- Post #36
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
t' / √1 - ( v / c )2 t' = 14 14 / √1 - ( v / c )2 14 / √ 1 - ( 269813212 / 299792458 )2 √ 1 - ( 269813212 / 299792458 )2 ( 269813212 / 299792458 )2 =0.80999999879 14 / √ 1 - 0.80999999879 1 - 0.80999999879 = 0.19000000121 14 / √ 0.19000000121 √ 0.19000000121 = 0.43588989574 14...- Rookie
- Post #33
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
Okay, okay give me some time I'll be back with a new answer!- Rookie
- Post #32
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
:( it's about 3am and my mind tend to drift. How about this 44.2718870949- Rookie
- Post #29
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
Okay is it this: 4.42718873898?- Rookie
- Post #26
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
Wait ignore that gold on.- Rookie
- Post #24
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
Oh I think I did do that! How about now: 19.9999998666?- Rookie
- Post #23
- Forum: Introductory Physics Homework Help
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Time Dilation, Spaceship Problem
I think I got it right, if not I'll post step by step. Is it 37.42?- Rookie
- Post #21
- Forum: Introductory Physics Homework Help
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Rocket Thrust, Acceleration, Velocity and Altitude
Not really sure what, or how to establish a general formula for 'net acceleration'. I reworked my equation including gravity and fixing the log/ln problem: v = v0 + u * ln(M0 / M) - g v = 0 + 400 * ln(4000/3625) - 10 v = 400 * 0.09844007281 - 10 v = 29.38 m/s How's this?- Rookie
- Post #11
- Forum: Introductory Physics Homework Help