Recent content by Rossy

Thank you for your time and patience with me! :) The problem is solved.

Is it right?

Can't get further...

So you can't get from this expression Y = A'B'C'D + A'B'CD + A'BC'D + A'BCD' + A'BCD + AB'C'D + AB'CD + ABC'D' to this expression by Boolean Algebra Y = A'D + B'D + A'BC + ABC'D'

So if I take this expression A'BC'D + ABC'D' I can simplyfy it like this BC'(A + D)(A' + D') but how do I continue?

Hi NascantOxygen, it's A'B'D Could you look at the image I uploaded, it's my attempt.. as you can see I can't get to the right solution.

uploaded pic

Homework Statement [/B] How to simplife it? I would like to see a process of simplification. Y = A'B'C'D + A'B'CD + A'BC'D + A'BCD' + A'BCD + AB'C'D + AB'CD + ABC'D' The ' denotes a bar over the previous letter.My second question is: Y = BC + AB'D = (uploaded picture) Y = A'D + B'D + A'BC +...