Recent content by rought

ok so I did part b here's what I got A(n) = 400,000 * 1.0075^n - 4000 * (1.0075^n - 1) / .0075 = 0 400,000 * 1.0075^n = 4000 * (1.0075^n - 1) / .0075 400,000 = 4000 * (1 - 1.0075^-n) / .0075 100 = (1 - 1.0075^-n) / .0075 1 - 1.0075^-n = .75 1.0075^-n = .25 1.0075^n = 4 n *...

Yes sorry, there is supposed to be a 9 in there... So there would be 999 "2"s ? Would there be 200 pairs of odd numbers?

Homework Statement Find the sum of the series 1-3+5-7+-11+...+1001 Homework Equations I have no idea on this one... I do know that the sum formula is Sn=n(t1+tn)/2

ah ok... so here's the equation that i got: An=An-1(1+.09/12)-4000 Is this correct? I'm not sure how to do part b now though... =/

Homework Statement In a Geometric Sequence find t10. t3 = 4 and t6= 4/27 Give a recursive definition for the sequence: 1, 4, 13, 40... Homework Equations I know that a Geometric sequence is: tn=t1(r)n-1 And that a recursive formula starts off with tn-1 I'm not sure where to go...

Homework Statement When Mr. Howe retires at age 65 he expects to have a retirement account worth about $400,000. One month after he retires, and every month thereafter, he intends to withdraw $4000 from the account. The balance will be invested at 9% annual interest compounded monthly. a) Let...

So would it be cosα = -3/5 tanα = -3/4 and sinβ = +3/5 cosβ = -4/5

ahh Ok so it's in the second quadrant which makes the x negative and the y positive so would that make cosα=-3/5 tanα=-3/4 and sinβ=-3/5 cosβ=4/5 is this right?

Homework Statement Suppose sinα = 4/5 and tanβ= -3/4 where π/2 < α < β < π (pi) Find: Sin(α + β) Cos(α + β) Tan(α + β) Sin2α Cos2β Tan2α The Attempt at a Solution What i have been doing is figuring out the other trig functions They gave me sinα=4/5 and tanβ=-3/4...

oo would I use the trig identity of: tan(2x) = 2tanx/1-tan^2x ? how would that factor out though =/ ?

Homework Statement Solve: tan2x + tan x = 0 I have no idea on how to solve this one =/

ah ok thanks a ton guys =]

the other one would be 5π/3 here's what I did tan^2θ=2tanθsinθ sin^2 θ/cos^2 θ=2(sinθ/cosθ).sinθ sin^2 θ/cos^2 θ=2(sin^2 θ/cosθ) 1/cos^2 θ=2/cosθ 2cos^2 θ-cosθ=0 cosθ(2cosθ -1)=0 cosθ=0 and 2cosθ -1=0

Homework Statement The Attempt at a Solution For #3 I need to finde the cos graph equation here's what I got: shift to the right 2, Amplitude = 3, b = π/2 equation: y=3cosπ/2(x-2) I'm just not sure if i have it in the right format or if I'm even right Attempt for #4...

ok I worked it out and i got: cosθ=0 and cosθ=1/2 which gave me π/2 and π/3 ... does that seem right?