Recent content by roupam

Ok, here goes... f^{-1}(x) = c^n/x^n f(x) = c/x^(1/n) which gives, f(f^{-1}(x)) = c/(f^{-1}(x))^(1/n) = c/(c^n/x^n)^(1/n) = c/(c/x) = x Again, f^{-1}(f(x)) = f^{-1}(c/x^(1/n)) = c^n/(c/x^(1/n))^n = c^n/(c^n/x) = x

Well, it seems right to me... f^{-1}(x) = c^n/x^n f(x) = c/x^(1/n) which gives, f(f^{-1}(x)) = x = f^{-1}(f(x)) And, I am not using the complex roots of x^(1/n), which I stated in the Preliminaries section of the paper that we are only working with positive reals... Thanks Roupam

Being a Comp. Sc. Student, I have the habit of using "i" :smile: Thanks, I will replace it with something like "a", or "r" etc. Can you please tell me why they are not inverses ? Isnt the inverse formula correct?

Hi, I have written a paper (attached) I would be happy to get comments on it Thanks Roupam PS. (Since, there is no independent research in the math section, I have posted here)

I need some feedback on a number theory paper of mine... I am not sure where to post it... Is it ok, if I post my message in the number theory section? Thanks Roupam