Recent content by roxxyroxx

Ultraviolet light question?? why is the term "ultraviolet light" misleading? is it because it is more on the violet end of the spectrum than violet light? any help please?

f = c/wavelength so wavelength = c/f = (3.00 x 10^8 m/s)/(5.50 x 10^14 Hz) = 5.45 x 10^-7 m ?

Homework Statement Yellow-green light has a frequency of 5.50 x 10^14 Hz. how many wavelengths of this light can fit into a space 0.500 mm wide? Homework Equations not sure .. xn/L = n(lambda)/d ?? The Attempt at a Solution ?

ok great thanks!

great thanks!

thanks! but y did u times by 2?

Homework Statement a cyclist and a car are approaching each other at the same speed. the car makes a 500 Hz sound at 343 m/s. the cyclist hears the sound as 535 Hz. How fast are they moving? Homework Equations f2 = f1(v/v\pmvs) The Attempt at a Solution 535 hz = 500 hz(343...

Homework Statement the radar on a ship sends out a signal which reflects off a rocky island 1500m ahead of the ship. how much time passes from the time the signal is sent until the reflection is detected? Homework Equations ? The Attempt at a Solution ?

Homework Statement a spectral line coming from a star in a binary system has a wavelength of 515.2 nm. in the lab the same spectral line would have a wavelength of 518.6 nm. what is the speed of the star in relation to earth? Homework Equations ?? The Attempt at a Solution ??

ookk thank you! >.<

ok so tan^-1(0.75/1.5) = 26.565... (1.33)(sin 26.565...) = (1.00)(sin theta) sin theta = 0.595 theta = 37 degrees but the answer is 54 ..

ok well i did sin(0.75/1.5) --> sin^-1(0.75/1.5) giving me 30 degrees so: (1.00)(sin 30) = (1.33)(sin theta) sin theta = 0.3759... theta = 22 degrees but the answer should be 54 degrees

Homework Statement A penny lies on the bottom of a pool 0.75m from the edge of the pool and 1.5m below the surface. A flashlight beam is shone over the edge of the pool to illuminate the penny. At what angle to the pool deck should the flashlight be aimed? Homework Equations ?? The...

thanks! ^^

Convex mirror problem help?? Homework Statement a convex mirror has a focal length of 75cm. an object with a height of 2.0m is 6.0m from the mirror. a) what is the distance from the object's virtual image to the mirror? b) what is the height of the object's image? Homework Equations...