Convex Mirror Image Calculation

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SUMMARY

The discussion focuses on calculating the virtual image distance and height for an object placed in front of a convex mirror with a focal length of -75 cm. The object is 6.0 m away from the mirror, leading to a virtual image distance (di) of -0.857 m when applying the mirror formula 1/f = 1/do + 1/di. The correct answer for part (a) is -0.67 m, indicating the need for proper sign convention. For part (b), the magnification formula m = di/do is used to determine the height of the image.

PREREQUISITES
  • Understanding of the mirror formula (1/f = 1/do + 1/di)
  • Knowledge of sign conventions for convex mirrors
  • Familiarity with the magnification formula (m = di/do)
  • Basic principles of optics related to image formation
NEXT STEPS
  • Study the sign conventions for concave and convex mirrors in optics
  • Explore the derivation and applications of the mirror formula
  • Learn about magnification and its implications in image height calculations
  • Investigate real-world applications of convex mirrors in safety and surveillance
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding image formation in convex mirrors.

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Convex mirror problem help??

Homework Statement


a convex mirror has a focal length of 75cm. an object with a height of 2.0m is 6.0m from the mirror.
a) what is the distance from the object's virtual image to the mirror?
b) what is the height of the object's image?


Homework Equations



1/f = 1/do + 1/di

The Attempt at a Solution


1/0.75m = 1/6.0m + 1/di
di = 0.857m

but the answer should be -0.67 for a and i don't know part b
 
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Use proper sign convension. Focal length of the convex mirror to be taken as negative.
For second part, use magnification formula. m = di/do
 


thanks! ^^
 

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