Recent content by royalewithchz

OHHHHH...my initial set up was wrong this: P(Ac∩Bc) and not this: P(AcUBc) the phrase "neither a nor b" confused me. I thought nor implied OR not AND.

Thats a clean method. Can I ask you why deMorgans doesn't work in this scenario?

Homework Statement A pair of dice is rolled once, what is the probability that neither a doublet nor the sum of 10 will appear Homework Equations P(A) = 1 - P(A') Demorgans law (AUB)c = Ac ∩ B c The Attempt at a Solution I know how to do the solution through brute force and...

Thanks!

Thanks Tycon, I really understood your explanation. Now i know how to do it 3 different ways, really neat!

solved. should be: Pr(A) + Pr(b) + Pr(C) + Pr(A)Pr(b)Pr(c) - (Pr(A)Pr(B) + Pr(A)Pr(c) + Pr(B)Pr(c))

Homework Statement Three people work independently at deciphering a message sent in code. the respective probabilities are persion a: 1/6 person b: 1/8 person c: 2/7 what is the probability that the message will be decoded Homework Equations (A or B ) = Pr(A) + Pr(b) - Pr(A...