i got the answer.
fringe spacing = ((wavelength)*L)/d
L = distance to screen
d = slit separation
the fringe spacing would be the inverse of 33fringes per cm or ((3300)/m)^-1 then just solve for d
Homework Statement
Using a conventional two-slit apparatus with light of wavelength 540 nm, 33 bright fringes per centimeter are observed on a screen 3.8 m away. What is the slit separation?
Homework Equations
m/x = (2*theta)/wavelength = number of fringes per meter
interence maxima...