Recent content by Ryan Lau

I believe I understand this comment now. Overview: To keep the vertical post upright, both the left and right side of the ground by the tensional strings will be equal to each other. 1500cos50 = 964.1814 N = Adjacent Side (floor) Cos Inv. (964.1814/2100) = 62.6688 N (angle required to keep the...

Unfortunately, I do not fully comprehend this explanation. My question is why 33 degrees is not the correct angle for Theta.

Homework Statement A vertical post is held in place by two cables as shown. Homework Equations SOH CAH TOA The Attempt at a Solution http://postimg.org/image/6rgssb1j5/ The answer in the textbook is 63 degrees. Is this an issue or did I do something terribly wrong?

Oh my heavens... Mr. Nathanael, I am terribly sorry... This entire time I was using radians! Brief overview. Force of Gravity Parallel = 147cos68 = 55.0672 N Force of Gravity Perpendicular = 147cos22 = 136.2960 N Force of Friction = (Mew * Normal Force) = (0.12)(136.2960) = 16.35552 MINIMUM...

147cos68 = 64.70102431 N ^ This is my adjacent, a.k.a. my Gravitational Force parallel. Should the opposite of it not equal to both the Tension Force and Frictional Force combined? I thought that is how equilibrium works. I am having difficulty finding the correct formula to solve. My...

http://postimg.org/image/x2lg95tj7/

Okay, I think I may be getting what you mean, however I end up with a diagram like this. Is there anything in particular that I am doing incorrect? http://postimg.org/image/nujh0ea99/ http://postimg.org/image/y9ir71kwn/

Tension force is minimum when force of friction is at it's maximum.

I noticed you mentioned static friction. Since the object is at rest, I believe that the static friction is somewhere in between.

My question now is, whether this stage could prove useful. http://postimg.org/image/l58u1qct9/

Well, I notice that both Tension Force and Force Friction are along the same path, therefore I believe those are the two variables?

Not certain, but if I calculate the Fgparallel portion, will I be able to calculate my Tension Force?

Homework Statement A 15kg block sitting on a 22(degree) incline is held stationary by a string as shown. The coefficient of friction between the block and the surface of the incline is 0.12. What is the minimum tension in the string? Homework Equations F=mg The Attempt at a Solution Drew a...