Recent content by Sabine

I am asking MATLAB to run a program I created. This program requires a huge calcul of integrals. If I reduce the number of integrals (which I can't if I want to study the real case) the program gives me a correct result. But if I keep it with all his calculs (nearly 1200 integrals), I have the...

we have 3 balls: 1 red, 1 green and 1 half red half green. 1-the probability to pick a certain ball of these 3 is:1/3 2-if after picking the ball, we were told that the ball contains the colour red (for exe.), then the probability of telling which ball it is becomes:1/2 (same thing for...

is the bermuda triangle a black hole? or is it just a magnetic field? where did the objects which disapeared in its atmosphere go?

well i tried i jst managed to find the solution i wrote before

hi monet 2sin^2 x = 1- cos 2x this means what u wrote is wrong .

it can be int(4- sin^2 x)/ cos^2 x dx = int(3+ cos^4 x)\ cos^2 x dx= 3(1+tan^2 x) + 1\tanx

please i need this now very urgent integral (2- (sinx)^2) * (2+ (sinx)^2) / (cos x)^2 please now

1=0.99999... true? x= 0.99999... 10x = 9.999999... 10x= 9+ 0.99999... 10x-x = 9 9x=9 x=1 =====> 1= 0.99999... is there smthg wrong?

but the occurrence of this event is barely negligeable compering with the universe in which i am studying the probability . for the 0+ this is its definition that's why i can't give u the exact number but u can find the 0+ maths books so i don't understand why u are discussing it it is a FACT...

0+ is the number that comes right after the 0 (0.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000...1) it is the smallest number after zero

in that case the probability is not 0 it is 0+ bcz this number may be found (sorry for my vocab i am french educated)

i've been thinking of it and i think it's indetermend

R ]-∞;+∞[ Є C (complex numbers) so what's the probability to find R in C? i think it is barely equal to more 0+

hurkyl 0^x=0 if x is different from 0 0^m*0^-m=0^0=1 or as i said before a^x=1\(a^(-x)) so if a=x=0 this means 0^0= 1\(0^(-0)) in this case 0^0 should b equal to one x^0= 1 even for x=0

i agree that 0^0= 1 a^x= 1/(a^(-x)) if a=x=0 then there is no way that 0^0= 0 because we'll have 0=infinite(1/0)