Recent content by Sagar98

@Doc Al , Thanks!

What is Angle of repose? All I know is something related to the body on an inclined plane slipping or at rest. Can someone explain?

Yeah, but in definite integration with limits you don't put the constant c..

@Simon Bridge, good question, at t=100s,There is No mass and no acceleration on it... So maybe.. It just goes at the velocity that it gained during first 100 seconds

@Simon Bridge, Refer to my solution , it's correct.

Mass of the cart is negligible, It's all the mass of sand.

Your method is wrong @dean Barry, the First post - The masses is constantly changing with time, so we don't know the velocity or the acceleration at 50s, So mass is a function of time here.

Yep correct ^ I did it by writing so calculations ain't as accurate.

@state of dogma, thanks..

I got it, It's like this, t-time taken v-velocity a-acceleration Now, (100-t)×a=100 That is ma=Force. But 100-t,as in that the mass reduces as the time increases. => (100-t)dv/dt =100 =>dv=100/(100-t) dt Now substitute 100-t as u, so dt =-du. Therefore => v=-100 integral du/u => v=-100...

@streamKing, Thanks, That makes sense. I got it. Thanks a lot.

Air*

See, a feather, or a piece of paper etc. Are exceptions, due to high aur resistance acting on then and low weight. I'm talking about say a 10kg iron ball the size of a soccer ball gets dropped. *suppose* from the stratosphere.. Which is I'm not wrong is 50km from the surface of the earth. So it...

A cart has a load of 100 kg sand at start and it is pulled by a steady resultant force of 100N starting from rest. A hole in the cart causes steady leakage of 1kg/s. Find velocity v of the cart after 50s of motion. What I know about this is that, we have to use calculus. dF =(dM /dT) *(dV/dT)...

Thanks, But is there any specific value for that velocity that once attained, the body stops acceleration?