Sagittarius A-Star's latest activity

This is not a full solution for problem (3b), but maybe a useful hint. When I substitute the RHS of (3b) into (3a), the two...

I think there's a subtlety here. ##U## is the 4-velocity of an observer at rest in the chosen frame. A charge at rest in the same frame...

Additional insight: The 4-vector ##E_{\vec U}^\alpha## from problem (3a), multiplied with charge ##q##, gives the Lorentz 4-force on a...

All of this is very helpful indeed! I'm going to try to work through the details on my own, so that I make sure I really understand and...

Apologies for the delay, but I'm still getting used to LaTex. Anyway, in answer to how I got to the expression(s) that left me stuck...

There is a Levi-Civita tensor ( https://en.wikipedia.org/wiki/Levi-Civita_symbol#Example:_Minkowski_space ), which is the volume element...

The following refers to special relativity. It is sufficient to prove the validity of the equation of part (b) in only one basis. This...

According to Wikipedia, this is a non-relativistic equation. The relativistic equation is shown below in Wikipedia...

What may help is the following hint in the description of problem #3: ##\vec{e}_{\hat 0} = \vec U## In special relativity, in the...

As delimiters, you can use double $ or double # on each side. See in below LaTex Guide link under "Delimiting your LaTeX code".

I think the implication is a similar phenomenon - the circumference of the rim grow unbounded, but this leads only to limiting area of 2...

That's infinite for any ##N##, not only for ##N=3##, due to the infinite last term ##i=N## in the sum.

For a rotating disk with only 3 rings (because of Wolfram Alpha calculation limitations): ##\lim_{v \rightarrow 1} {E/M} =## ## \lim_{v...

That is in accordance with the result by OP, who obtained ##KE=E-M=M##, which implies ##E=2M##. This demonstrates that my removal of the...

I get from Wolfram Alpha 44.676683503771391589009225229630072178116008914652013623324856498 Calculation