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What is the Last Term in the Expression for \nabla\cdot(\phi\vec{A})?
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- Forum: Calculus and Beyond Homework Help
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What is the Last Term in the Expression for \nabla\cdot(\phi\vec{A})?
Homework Statement If \phi= xy^{2} A=xzi-z^{2}j+xy^{2}k B=zi+xj+yk Verify that \nabla.(\phiA)=A.\nabla\phi+\phi.\nablaA Homework Equations The Attempt at a Solution I have worked out the first two parts of the question: \phiA = (x^{2}y^{2}z, -xy^{2}z^{2},x^{2}y^{4}) div(\phiA) =...- SAMSAM12
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- Forum: Calculus and Beyond Homework Help