Recent content by Sara583

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    Moment of inertia and angular velocity of a uniform disk

    Thank you very much! I did manage to solve it in the end using your hints about energy loss.
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    Moment of inertia and angular velocity of a uniform disk

    I know that K = 1/2 Iω^2 but I'm still a bit unsure how to calculate the total energy beforehand. Am I missing something?
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    Moment of inertia and angular velocity of a uniform disk

    here is the diagram for the problem: My working for part a was) parallel axis theorem: Icentre of mass + md^2 d= b , total mass = 6m (ma^2 + ma^2+ 1/2(4m)a^2)+ 6m(b)^2 2ma^2+2ma^2+6mb^2 4ma^2+6mb^2 Hopefully it makes more sense with the diagram now. The program has marked my answer has...
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    Moment of inertia and angular velocity of a uniform disk

    Homework Statement Two particles, each of mass m, are attached one to each end of a diameter PQ of a uniform circular disk, of mass 4m, radius a with its centre at O. The system is free to rotate about a horizontal axis through A, a point on PQ such that OA = b as indicated in the diagram...