Recent content by sarahmf

Alright so if I solve for P2-P1=rho*g*h I get 0.0582 m=5.82 cm, which is recognized as right..thank you so much :)

Alright so Flow=A*V V1=Flow/A1 =1131.0/(pi*(1.13/2)^2) V1=1126 cm/s V2=Flow/A2=1131.0/(pi*(0.36/2)^2) V2=34907 cm/s P1-P2=.5rho*v2^2 + rho*g*h2 - .5rho*v1^2 - rho*g*h1 P1-P2=.5*1.28 kg/m^3*1m^3/1000000 cm^3 (is my conversion right) * 34907^2 + 1.28/1000000*9.8*h2 -...

Homework Statement The following tube has dimensions d1=1.13 cm and d2=3.60 mm. Air (density = 1.28 kg/m3) flows through the tube at a rate of 1131.0 cm3/s. Assume that air is an ideal fluid. What is the height h of mercury (density = 13600.0 kg/m3) in the right side of the U tube...