Recent content by saulwizard1

Ok, thank you so much for the help.

10V-(6 ohms*I)=0 10V=6 ohms*I I=10V/6 Ohms I=1.66 A

Yes, I didn´t see the sign So it would be VT=2+3+5=10V

The first one is=-2 The second has the same polarity, and it has a rise of potential For the third, it has the same polarity and it has a rise of potential. that's correct?

VT=2-3+5=4V it's correct?

According to the Kirchoff's law of voltages: RT=6 ohms VT=? -2+3-2I+5-4I=0 6+-6I=0 6I=6 I=6/6=1A is the result right? I have some doubts in the signs of the voltages.

If all it's Ok, I think that this exercise is solved, thanks for your help with this problem.

I made a procedure and I get that the voltage=4.8V and the current for the resistance of 3 Ohms it´s equal to 1.6A, am I right?

According what I understand, the 2.4A would help me to get the voltage using Voltage=(current)(resistance), or in what way can it help me?

I know that the sum of the currents in the circuit must be equal to zero and that the algebraic sum of the voltages must be equal to zero, I know this because I am self studying this topic, bue I don't have idea of the procedure to follow.

Homework Statement Hello, can you help with this problem. For the next circuit, determine the voltages Homework Equations I=V/RT RT=R1+R2+R3+...+Rn P=V^2/R V=V1=V2=V3 I=V/R GT=1/R1+1/R2+1/R3+...+1/Rn The Attempt at a Solution My background is that I only know a very few and I don´t know how to...

Homework Statement Find the current for the next circuit. Consider the values given: V1= 2 V, V2=3V, V3= 5V, R5= 4Ω Y R4= 2Ω Homework Equations RT=R1+R2+R3+Rn I=V/RT P=VI=V^2/R The Attempt at a Solution My attempt of solutions is to sum the first two voltages and divide it between the first...

Homework Statement Solve the next circuit to find the voltages Homework Equations I=V/R GT=(1/R1)+(1/Rn) V=V1=V2=V3 The Attempt at a Solution My background is that I know that in a parallel circuit, the voltage for each component is the same and electric current it's equal to the sum of the...

Thank you so much, I really appreciate your help and that you shared your knowledge with me!

Another question, this method only applies in cases similar to this one, cases in which the probability is less than one? In a case when I already have the probability equal to one, do I only need to evaluate the function in the intervale (a,b) or I have to do another procedure?