Parallel Circuit Voltage Calculation: Solving for Voltages using Ohm's Law

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Discussion Overview

The discussion revolves around solving a homework problem related to calculating voltages in a parallel circuit using Ohm's Law. Participants explore the relationships between current, voltage, and resistance in the context of the given circuit.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states that in a parallel circuit, the voltage across each component is the same, and the total current is the sum of the currents through each resistor.
  • Another participant questions the clarity of the problem statement and asks for clarification on what is meant by "Solve the next circuit," suggesting that the original poster should provide more details.
  • Some participants express confusion regarding the application of given currents and resistances, particularly questioning the motivation behind multiplying 5A by 3 ohms.
  • A participant mentions that the current of 2.4A could be used to find voltage using the formula Voltage = (current)(resistance), seeking clarification on its usefulness.
  • One participant claims to have calculated the voltage as 4.8V and the current through a 3-ohm resistor as 1.6A, asking for validation of their results.
  • Responses indicate that the calculations presented by the participant appear correct, with some affirming the results without further elaboration.

Areas of Agreement / Disagreement

While some participants affirm the calculations presented, there is no explicit consensus on the overall solution or clarity of the problem statement. Multiple viewpoints regarding the interpretation of the problem and the calculations remain evident.

Contextual Notes

Participants express uncertainty about the completeness of the problem statement and the implications of the given currents and resistances. There are unresolved questions regarding the application of Ohm's Law in this context.

saulwizard1
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Homework Statement


Solve the next circuit to find the voltages

Homework Equations


I=V/R
GT=(1/R1)+(1/Rn)
V=V1=V2=V3

The Attempt at a Solution


My background is that I know that in a parallel circuit, the voltage for each component is the same and electric current it's equal to the sum of the electric currents of each one of the resistances by separate. My first and only attempt was to multiply the 5A by 3 ohms.
 

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Your problem statement is not clear or complete. What do you mean by "Solve the next circuit"? Solve for what? Please make an effort to provide clear problem statements that can be readily understood by the Homework Helpers.

What was your motivation for multiplying 5A by 3 Ohms? What about the 1A source and the other resistor?

Hint: You are given a current through one of the resistors. Does that give you any useful voltage information?
 
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gneill said:
Your problem statement is not clear or complete. What do you mean by "Solve the next circuit"? Solve for what? Please make an effort to provide clear problem statements that can be readily understood by the Homework Helpers.

What was your motivation for multiplying 5A by 3 Ohms? What about the 1A source and the other resistor?

Hint: You are given a current through one of the resistors. Does that give you any useful voltage information?

According what I understand, the 2.4A would help me to get the voltage using Voltage=(current)(resistance), or in what way can it help me?
 
saulwizard1 said:
According what I understand, the 2.4A would help me to get the voltage using Voltage=(current)(resistance), or in what way can it help me?
Review your own Attempt at a solution content, the answer's there!
 
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gneill said:
Review your own Attempt at a solution content, the answer's there!
I made a procedure and I get that the voltage=4.8V and the current for the resistance of 3 Ohms it´s equal to 1.6A, am I right?
 
saulwizard1 said:
I made a procedure and I get that the voltage=4.8V and the current for the resistance of 3 Ohms it´s equal to 1.6A, am I right?
Looks good.
 
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gneill said:
Looks good.
If all it's Ok, I think that this exercise is solved, thanks for your help with this problem.
 

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