I'm not very familiar with statistics, so that's my main problem.
I use a least squares software to generate the coordinates of points and their associated 95% error ellipses. If the error ellipses meet a certain pre determined tolerance then I'm done.
However, I have a situation where I have...
OK, so a LONG time ago I believe I saw a small drawing by Newton which represented the first true drawing of a Cartesian graph with an x and y-axis and "O" at the origin.
Now (that I'm old and can't remember what I had for breakfast) I'd like to find it but can't remember where it was.
Any help...
Sorry, 30 years since college and I wasn't awake all the time.
I'm trying to translate the symbology in the attached pics.
Some of the super/subscripts are throwing me off in formulae 13, 14 and 15.
Y and X = planar coordinates of points.
n = number of points.
σβ = standard error of angle...
Is there a relatively simple algorithm to compute the area in percentage under the curve as represented by a sigma value?
For example;
3 sigma = 99.7
2 sigma = 95
1 sigma = 68.3
Now suppose I wanted to know 2.5 sigma without a table.
Can anyone point me towards a listing of common star names for the FK5?
I've been going through Wikipedia, one star at a time compiling common name, constellation and greek letter for the FK5 and I have lost my enthusiasm after a hundred or so stars.
Surely someone (with more fortitude)...
Right, sorry.
Right Ascension and Declination are spherical coordinates for stars etc., where declination equals latitude and right ascension longitude.
http://en.wikipedia.org/wiki/Celestial_coordinate_system
OK, I'm really rusty on this.
I need to convert a unit vector to right ascension and declination.
I believe I recall the formulae correctly, as I seem to have gotten 1 as my radius.
So, that's good.
In the pic I have my unit vector (P2), my actual answer below, my expected answer in...
Woohoo!
Thanks gneill, with a little tweaking of the values I managed to get the answer in INCHES and then converted to feet and looks like I'm golden.
Thanks again.
g = 9.81m = 32.17405 ft
x = 999.126m = 3277.972 ft
A = 10.2mm^2 = 0.003 inches (from manufacturer - I get 0.034 feet)
E = 2x10^5 N/mm^2 = 29,700 KSI (from manufacturer of tape)
M = 0 = 0 (theoretically any attached weight kgs in orig/lbs...
gneill,
That is it in a nutshell. I took a few tries at it and cannot reproduce the metric result with "english" units.
I added a jpeg of the text explanation if that helps.
I have attached a pic which really explains the formula and context of the problem.
I'm guessing a gravitational effect passes for physics...
I am trying to convert the formula in (b) below into feet.
If I could reproduce the answer with English units, I could move on and apply the...
I have attached a pic which really explains the formula and context of the problem.
I am trying to convert the formula in (b) below into feet.
If I could reproduce the answer with English units, I could move on and apply the formula to other situations, but the multiplicity of English...