Recent content by scubakobe

I guess that's true, however in my classes so far we've only referred to points, and not "critical lines." So the answer would be no critical points? The 2∏ intervals are simply a recurring minimum value, but not necessarily a local minimum.

Yes, x can be anything as long as the y=2∏. For both the f_{x} and f_{y}. So the x can range from 0\rightarrow∞, but the only time the first partials will equal 0 is when y=2∏. Or even multiples, as I had said. So here's the second order test... D(x,y)= f_{xx}(x,y)f_{yy}(x,y) -...

Yes, that's where I'm having trouble. My thought is, and another post (Which I can't find now, sorry) suggested, is that ex cannot equal zero - so x would have to be equal to 0 in order for the ex to become 1. A graph in WolframAlpha suggests a saddle point; and it does confirm 2∏ as the...

Yes, sorry forgot to include that: fxy=exsin(y)

1. If f(x,y)=e^{x}(1-cos(y)) find critical points and classify them as local maxima, local minima, or saddle points. The Attempt at a Solution I found the partials and mixed partial for the second derivative test as follows: f_{x}=-e^{x}(cos(y)-1) f_{y}=e^{x}(sin(y))...