Recent content by sdekivit

chlorate = ClO_{3}^{-}. What is the exact question here though ?

Another way would be the use of Avogadro's number.

use the first law of thermodynamics: Q + W = \Delta E_{pot} + \Delta E_{kin} --> the process is adiabatic, thus Q = 0. The gas is compressed. Acoording to W = p\Delta V[/tex] W < 0 Because the increase in potential energy is neglectable, \Delta E_{kin} > 0, because of conservation of...

sounds OK to me :) this formula is kind of logic, because when you have the reaction say 2A + B --> 3 C with R = x (mol/L*s) then when we look at the reaction equation we see the when the overall reaction rate is x then A will react twice as fast. that's why R = - \frac {1} {2} \frac...

for problem 1 & 2: asumme we have 100 different isotopes. Then for problem 2 of the 100 Re-atoms, 62.6 atoms are Re-187 and 37.4 atoms are Re-185 The you only need to use the formula you use for every calculation of the average: \bar{a.m.} = \frac {(62.6\cdot185.956) + (37.4\cdot...

let's see what you've tried and then we can give hints that leads you to the correct answer(s)

The second is correct, because H2CO3 doesn't exist in a solution and always dissociates in H2O and CO2. none are correct, since you have equal amount K+ on both sides of the arrow so they cancel each other out. But apart from that i would go for the second one. assume the reaction takes...

e^{ln(1+e^{x})} = e^{x} 1 + e^{x} = e^{x}

According to 'Microbiology' by Prescott, Harley and Klein: A pathogen is any disease-producing microorganism.

draw yourself a triangle and note that sin \theta = \frac {d_{minumum-central finge}} {d_{slit-screen}}

if we assume coins to be circular, the surface area of the coin can be calculated with \frac {1} {4}\cdot \pi\cdot d^{2} If you know what the increase in mass of the coin is, you know how many grams of the atoms of the solution is added to the coin. you can convert that to amount of atoms...

for the acids HF,HBr,HCl,HI the atom radius is of importance.

CF3-COOH is a strong acid and dissociates completely in water and that can be the reason you can't find any K-value. I assume this because Ka of CCl3 - COOH is 2,0 x 10^-1 (it's directly under H3O+ in my table)

fluorine has the highest electronegativity and thus pulls the electrons of OH-groups in the COOH-group towards the itself, making it relatively easy to lose the proton of the carboxylgroup. Structure: CF3 - COOH (electronegativities: F = 4.1, Br = 2.7, I = 2.2, Cl = 2.8 and H = 2.1)

They ask for the position of the object, thus in my opinion the object distance.