Thanks, that did help a bit, but I'm still concerned about having a dimensionless value divided by radians...in this case, our slope is supposed to represent μ, which from my understanding does not have any units. So does this mean that radians isn't really a unit either?
Homework Statement
In a physics lab we were finding slope on semi-log graph paper, with the y (up) axis representing tension in Newtons, and the x (sideways) axis representing θ in radians. Sadly, the prof introduced the new concept of natural logs to me - I'd never heard of these until this...