Recent content by SenseAO

Figured it out.

yes, uniformly across the bar

The 16mm corresponds to the bar

Does not specify. So than we would just do 25kn/0.016m = to give us 1562.5kNm converting this to Nmm would give us 1562 x 10^6 Nmm am i somewhat right?

The cross sectional area of the beam?

F/A? Force being 25kn and the area being 16mmx16mm?

Yes i have and i get the picture in my head. But i just can't place where the 16mm goes.

A steel bar that is 16mm in diameter is resisting a force of 25kN. What is the normal axial stress in the bar(MPa) Since MPa = N sqmm would it be 25kn/(0.016m x 0.016m) Im more after the process on how to get the answer than the answer itself.