Recent content by Sequence1123

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    Work done by friction on a skier and resulting distance the skier travels

    AH! I figured it out... I had to find the length of the bottom of the triangle formed by the horizontal and the slope of the hill. sin20° = 20/x (where x is the hypotenuse, or the length of the slope of the hill) from that I got x ≈ 58.5m Then, cos20° = x/58.5m (where x is the length of...
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    Work done by friction on a skier and resulting distance the skier travels

    Homework Statement A skier starts from rest on a 20m high, 20° slope. μk=0.210 Find the horizontal distance traveled by the skier. From this, for the equations below we know that: yf = 0 vi = 0 vf = 0 Homework Equations Wnet = Wnc + Wg = ΔKE Wnet = -fkd Wnc = ΔKE + ΔPE Wnc = ΔKE + mg(yf - yi)...