Recent content by Serotonindude

ah! now i understand that first question of yours in the right way! yeah, there was already the answer in there, i just didn't get it at that time.

Well the conversion factor should be 1 solar mass in kilogram... so 1.9884 · 10^30 kg ... mass of Earth shouldn't enter the conversion, since it's just another mass (which needs to be converted as well of course, but it has nothing to do with G). So actually it should be G_mine = G * m_sun =...

how do i reply to an answer? anyway, it's the ratio of the Earth's mass to the sun's mass... it is indeed in this order of magnitude... m_earth = 5.974 · 10^24 kg / m_sun = 1.9884 · 10^30 kg = 3.044 · 10^-6 ... it's the normalized masses I've used...

5.974 · 10^24 kg / 1.9884 · 10^30 kg = 3.044 · 10^-6 think 3 million is still enough :)

hi, i'm totally confused right now. I'm playing around with a simple orbital model of the sun and the earth. since my rigid body solver doesn't like the huge masses of those bodies, i just normalized the masses to those of the sun. so i have m_sun = 1 and m_earth=3.0044e-6 as dimensionless...