Recent content by sgod88

But now V(x,y,z)=V(z), where V is not a function of x and y anymore. With this condition, in x and y, the wavefunction is certainly not zero, it is a free particle. \psi_{x}=e^{i(kx-wt)}

1. Quantum well structure can be realized by sandwiching layers of semiconductor and two insulators. This sandwiching problem was often treated with 1 D infinite well. Suppose now the problem is 3 dimensional well with length L at z direction from 0 to L, at which V(x,y,z)= 0 when 0<z<L...

a) Yes I could do that. It is \psi=\int_{20}^{20+a}{\frac{\mu_{0} I(t)(100-a)}{2\pi y}}dy} = \frac{\mu_{0} I(t)(100-a) }{2\pi}}ln(\frac{20+a}{20}) Then I got the answer I mentioned by making assumption for impedance matching. Thank you! =)

Sorry I that I mentioned the B is constant, it varies with time. I think so it has y dependence because B field changes as y changes (B field itself is varying with time and space cos of the current I and the distance between the wire and the copper wires) and the B field for infinitely long...

Yes the copper loop is 20 m from the power line and B is assumed to be constant. EMF induced in the loop should be depending on the area of the loop, where V_{ind}=-\frac{d\Psi}{dt} and \Psi=\int{BdA} =\frac{\mu_{0} I}{2\pi}\int\int{\frac{1}{y} dy}{ dx} For part b, you mean that the...

1. I have encountered a problem on power extraction in Faraday's Law application. Consider I live out in the country and I suddenly realized that a power line of current I=I0cos(2pi*60t) [A] is situated 20m from my farm. A copper wire of diameter 4.1mm, 200 m in length was found in the garage...