Recent content by shahper

Oh, I mean the situation where the switch is closed, and LED is on (i.e the primary side of the circuit is conducting). I'm extremely sorry for the confusion.

I'm talking about the emitter of the phototransistor. If it is not connected to the ground, then what will be the voltage at Vo. In this case, I believe primary side of the circuit will be working. And further more, if transistor is in cut-off mode (i.e not conducting), than I believe Vo will...

Hello all, If in this http://en.wikipedia.org/wiki/File:Optocoupler_Circuit.svg" , Emitter is not connected to the ground, what will be the voltage at Vo and and at the Emitter? Thanks