Recent content by shaka091

Thank you very much for your reply! I followed all the steps in my lecture notes to reduce it and thought it was correct but I thought I must have got it wrong when i then put it into the runge kutta as i was getting back some pretty big values. Evaluating y(1.2) using a step size of...

Hi guys I was hoping if someone could help me with this second order differential equation which i have to reduce into a series of first order equations and then solve using a fourth order runge kutta method. The equation is y"-30y'-3y=-2 with the initial conditions y(1)=-12 and...

Thanks for your help, lol turns out I should have just used this formula M=F*D with distance being (300^2+250^2)^0.5 * F = 280

Ok so, r=0.25i + 0.075j + 0.30k because the force points in the -j direction I got, (0.075*0)-(0.30*-Fj) = 280Nm which then got F=933.33 ?

Ok so I r=250i + 75j + 300k And F is unkown. Because the moment is around the x axis, I got something like this (75*z)-(300*y)=280Nm But wouldn't know where to go from there.

Hey guys I was hoping you would be able to solve this question for me with a worked solution :) And also this question, thanks a lot :)