Recent content by SherlockLCooper

it worked!

ill try this and let you know! Thank you so much!

(100)/(2)(9.8)((3^(1/2))/2)=5.89 meters

(2mg cos 30)/m=a=v^2/r m cancels so v^2/2gcos30=r

30 degrees!

so all the velocity would be in the horizontal plane?

I want to say (T Cos(theta)i, T sin(theta)j) where the y component would be T Sin(theta)=mg..? so t/mg= 2, so sine (0) =0, so it is in the horizontal plane, the alternative T Cos(0)= T*1= T.

does this help

thanks!

t=tension. and I have drawn diagrams, and i just, tried v^2/2g, and it was also incorrect, am i using the right Equations?

this is all the information I was given, I imagine the angle too, but I have no value for theta. is that something I can solve for with the information given?

Homework Statement The County Fair Swing carries the mass of riders and chairs in a circular path in a horizontal plane while suspended by cables or chains. Let's assume that: Each chair with riders is supported by a single cable The tension in the cable equals 2 x the total weight riders...