Recent content by shocked_prawn

@BvU Brilliant thank you for your help :cool:

Hi @BvU Thanks for the help :) Whilst working on it over the weekend I have used the product of volumetric flow rate and density for now (thank you!) In the textbooks, it says that the relationship between mass and volumetric flow rates for a compressible fluid is more complex than that for a...

I have converted given pressures from bar gauge to bar abs Inlet pressure = 20 - 1.013 = 21.013 bar abs Outlet pressure = 6 + 1.013 = 7.013 bar abs therefore pressure drop (x) x = {p_1 -p_2 \over p_1 } = {21.013 - 7.013 \over 21.013} = 0.6662542236 bar abs Comparing to the chart values for...

Hi, where did you get the calculation for xT from?