Recent content by Sierra

I might be confusing myself. There's only two electric fields to choose from and I've used both of them and they are both wrong apparently. I'm looking for the charge of c. But am I missing something? Like c is the opposite of a?

Omg so C is zero and the net charge for b 4.00??

I found C by doing 3600(0.2m)^2/ (8.998x10^9) = 1.6x10^-8

I redid a and I got 1.8x10^3 V from ΔV= Kq/r from which it is (8.998x10^9)(10*10^-9)/ (0.05m)

My mistake. C) I got 1.6x10^-8.. changed it to 1.6x10^-9 to match D. B) (1.6x10^-9) + (6.0x10^-9) = 7.6 x 10^-9 nC

For a I got -4.00x10^-9 nC B) 3800 N/C from 3600 N/C + 200 N/C C) 0 nC from q= 0 N/C (0.2 m)^2 / (8.998x10^9) D) 6 x 10^-9 nC from 200 N/C (0.5 m)^2 / (8.998 x 10^9)

Ok, I changed my answer from b to answer d. I solved for C and got -7.96x10^-11 from q(inner)= -Q(i used my answer from a to get this Q) / 16pi(0.02)^2. And I got my net charge for b to be 5.48x10^-9 after adding c and d together

Then for c it is 0 because it is the conductor and for d I just used the same as the other one and got 4x106-9

For b I got Q= 5.56x10^-9 because I used E=kQ/r^2 and solved for Q to get Q= Er^2/k and used the charged found on 50 cm, the 200 N/C and plugged everything into its respectful places

So use flux? That would mean that Φ=EdS* Q/ε(o)?

So I would use the electric potential equation to get a correct? Just fill what is known? So U=(8.998x10^9)(10x10^-6)(0.05) / (0.02)? Or since you asked what is the relationship. Would it be equal of each other?

So what equation would I use to get that? E or U?

Homework Statement A ring of charge is situated in the x‐y plane centered about the origin. The ring has a uniformly distributed charge Q = ‐10 nC and a radius R = 2.0 cm. a. Find the electric potential at a distance z = 5.0 cm above the origin on the z=axis. b. Find the electric field at a...

Homework Statement A solid insulating sphere of radius 5.0 cm shown in blue has a uniform charge density throughout its volume. Concentric with this sphere is a conducting thick hollow spherical shell of inner radius 20.0 cm and outer radius 25.0 cm shown in grey. The electric field at a point...

Nice to meet anyone who reads this. This is my first time here so I hope that I get to learn a lot since I'm in physics 2 at my college :) Thank you!