Recent content by SigurRos

Our math professor gave us this take-home project: Consider a solid in the shape of the region D inside the surface x^2 / (z^3 - 1)^2 + y^2 / (z^3 + 1)^2 = 1 If the density of the solid at the point (x,y,z) is x^2 + y^2 + z^2 then determine the mass of this solid. A GOOD CHANGE OF VARIABLES...

Good news: I got the solution.

I got this question as a take home exam question, and I can't figure it out for the life of me: The temperature T(x,y,z) throughout a region in space is given by: T(x,y,z) = 3*x^2*y*2+z^2 An insect is confined to move on the surface S : x^2 + y^2 = z. The insect is at the point...

Maple computed the derivative for me, and that is what it gave me. Also, I did use those 2 points to construct 2 equations, but when I tried to solve for the system I got a complex equation with lots of cosh's that maple couldn't solve.

Hey I got a project assigned for my Calc 3 class, and I was wondering what to do with the following: A hanging cable has the shape y = 1/c cosh(cx + b) + a for some constants a,b,c with c>0. Suppose the ends are at P(0,10) and P2(30,5). If the length of the cable is known to be 100...

Im a first year mechanical engineering student, and I think that I would like to do work with particle accelerators (beam physics and technology). Does anyone have any recommendations as to what specific degree(s) I should look into, and which schools have great programs? Thanks!

awesome! you rule as do i, but to a clearly lesser extent

and therefore, i end up with 2x/e * infinity, and therefore the radius of convergence is 0 right?

with this new knowledge, imust now include (2n+1)in my limit, which is not pretty, as it produces infinity. correct?

i hereby retract my previous statement you are right, mathphys i was wrong thank you for showing me the way (calculators don't lie)

i don't think that's so, because all n is replaced with (n+1), making (2n)->2(n+1)->2n+2. To get 2n+1 you'd have to add a n value of 1/2. if you divide out 2n+1, you'd get 2(n+1/2) which is incorrect, i think. im pretty sure that the way this series works, it is only 2n+2, or 2(n+1) i...

im pretty sure the factorial is right because when (2(n+1))! is divided by (2n)!, it equals (2n)!*2(n+1)/(2n)!, which cancells out to 2(n+1) ...right? and i checked that limit with maple and it gave me e^-1 wait a minute, is 4x/e, therefore x=e/4 because of the manner of this particular...

well (1+1/n)^(n+1) is e and 1 + 2/n)^(n+1) is e^2 so it would have to be 2x*e^-1, or 2x/e, right? or am i missing something 2 hours till test... i love caffeine

wait, for the second power series, after some manipulation, wouldn't you end up with 2x* Lim((1+1/n)/(1+2/n))^(n+1), which would be 2x/e, and the radius would be e/2?

...i didnt mean to start a fight i just wanted homework help feel free to continue though, I am not really knowledgeable on logic and proofs, so maybe i can learn something from this debate Thanks again for your help guys