Recent content by silvetriver

yea that's what i think to start with but i can't find f(x) and f(0)

yessss i just realize that f(0)=f(a*0)=a^lambda f(0), well then i totally get lost...

oh sorry i mistyped the problem. it should be f(ax)=a^lambda f(x) I think 1^lambda=1 because the problem states that lambda>1

You are right that's what i mean. yea ^ means exponentiation...

how can i use epsilon delta to prove differentiability?

Homework Statement Mod note: Edited the function definition below to reflect the OP's intent. [SIZE=14px][FONT=verdana] Suppose f:R->R is continuous. Let λ be a positive real number, and assume that for every x in R and a>0,f(ax)=aλ f(x). (a) If λ > 1 show that f is differentiable at 0. (b) If...