Recent content by Simon_G

Why? Isn't he human? :D Anyway, relation above hasn't free indices: g^{\mu\nu}g_{\mu\nu} so it has to a scalar. Indeed it is dimension of manifold. Sorry for my poor english :D

This relation is wrong. g^{\mu\nu} g_{\mu\rho} = \delta^\nu_\rho then, if we take \nu = \rho we obtain: g^{\mu\nu} g_{\mu\nu} = \delta^\nu_\nu but the last term is the trace of Kronecker delta which is four if dim(M) = 4

Locally it seems a 1-form and since there is a one to one correspondence between 1-form and vector field so potential can be viewed as vector field. But if we take a gauge transformation we discover that it transforms as a principal connection on a principal bundle... For Maxwell theory...

Actually, electromagnetic potential is a principal connection

Curvature form with respect to principal connection Hi all, I have a question. Let us suppose that P is a principal bundle with G standard group, \omega a principal connection (as a split of tangent space in direct sum of vertical and horizontal vectors, at every point in a differential way)...