Recent content by SiRiVeon

Thank you sir. So if I consider the ball as a point mass then before touching the bottom of the slope, the conservation of energy of the ball will be mgh = (1/2)mv² and since it has to pass the loop with that energy, the equation will be mgh = (1/2)mv² = mg(2R). Therefore by solving, the height...

Okay. I think the circle is more like a Diavolo loop where Newton's law gives us -Fₙ -Fg = m(-v²/R) or mv²/R = mg. Solving this I get v = √(gR) which is the minimum velocity needed to move around the loop. By putting the equation of v into mgh = (1/2)mv² + (1/5)mv² and solving it, the height I...

There's no radius mentioned for the black ball so I assumed it has a radius r. Radius r can be allowed to have value but I was hoping if it can be solved without any complexities of ball radius. I just need to know what the height of the triangle needs to be, if it can be solved other than...

Hello, this question may seem weird but I really need help on this. To bring the formula for the height h of the triangle above, I have to create a relation between potential and kinetic energies of the black ball with mass m (I can't find any other methods than this). For a sphere falling...