Recent content by SiYuan

That's right, use this to find the number of molecules in individual tanks, then you should be able to get the answer for pressure.

There is something faulty about this. The initial KE of Ball 2 should not be 0, but instead 1/2 (m)(26.241)^2. And after calculation, the final velocity still gives me the same answer I had during kinematics. Your professor has made the mistake that (Vf + Vi)^2 = Vf^2 + Vi^2

Hahaha redeem myself. O Yes I will sire. I suppose I will give this a shot. (a) Follow the hint, the heat gain by 1 tank = heat loss by the other. Hence the temperature should be averaged out by the two. And what's the average between 220 and 580?

Have you missed out anything from the question?

What is the answer?

I'm sorry I can't help you for this. Im also studying Physics at this moment and the Carnot engine is not in my field of studies. So I suppose your first line is wrong then :)

That'd be fine, as long as I can answer it.

My pleasure, copitlory8

If you did the kinematics method (V^2 = U^2 + 2AD), you should get the final velocity which is after addition already.

It should be right, yes.

Your unit conversion is wrong, if you were to use m^3 you should get something else.

Yes, it is 2 dimensional, but Ball 2 experiences only vertical velocity, since it is thrown straight down.

The average density of water should be 1g/ml, or 1g/cm^3, whilst 1.94 is for lb/ft^3 if I recall right.

Yep, as I mentioned earlier, the velocity for Ball 2 would be the initial velocity + the additional vertical velocity, which is found by V^2 = U^2 + 2AD as well

The density of water is 1.94 for feet^3, while your question is in m^3