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Correlation coefficient of two-particle half-spin entangled state
I think I might be on to something with this, but am not quite there yet: \hat{S}_z =\frac{\hbar}{2} \begin{pmatrix}1 & 0 \\ 0 & -1 \\ \end{pmatrix} Rotate by angles \theta, \phi to get \hat{S}_\phi = \frac{\hbar}{2} \begin{pmatrix} \cos \theta & \sin \theta e^{-i\phi} \\ \sin \theta...- Skiggles
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- Forum: Advanced Physics Homework Help
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Correlation coefficient of two-particle half-spin entangled state
Hi, I can't get my head around this question. Homework Statement The Bell state: |\psi\rangle = \frac{1}{\sqrt{2}}\left(|\uparrow_1\rangle|\downarrow_2\rangle +|\downarrow_1\rangle |\uparrow_2\rangle \right) Find the correlation coefficient of the measurement of the spins in the directions...- Skiggles
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- Coefficient Correlation Entangled State
- Replies: 1
- Forum: Advanced Physics Homework Help